This program receive two numbers and compute the sum of geometric progression. The program implements the geometric progression and output the results when it receives the inputs.
Learn C programming concepts before you start with this example program. Continue reading if you are familiar with the basics.
- C Program Structure.
- How to Install Turbo C++ Compiler?
- C Printing Outputs.
- C Reading Input Values.
- C Data Types.
- C Arithmetic Operators.
- C For Loop.
Problem Definition
A geometric progression has two conditions.
where is the first term and not equal to 0. for
\begin{aligned} &Suppose \hspace{2px} a = 1 \hspace{2px} and\hspace{2px} r = 5, \hspace{2px} then\\ \\&a_1=1\\ &a_2= 5,\\&a_3=25\\& a_4= 125\end{aligned}
Basically, you can compute any term using the following formula.
\begin{aligned}a_n \hspace{1ex} = \hspace{1ex} a \cdot \hspace{1ex} r_{n-1}\end{aligned}
The summation of a geometric progression is given below.
\begin{aligned} 1\hspace{1ex} + \hspace{1ex} x \hspace{1ex} + \hspace{1ex} x^2\hspace{1ex} + \hspace{1ex} x^3 \hspace{1ex} + \hspace{1ex} x^4 \hspace{1ex} + \hspace{1ex} \cdots \hspace{1ex} + \hspace{1ex} x^{n-1} \hspace{1ex} \cdots\end{aligned}
The summation can be translated into a program for any given
Program Source Code
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
int geo_sum, i, x,n;
geo_sum = 1;
printf("Enter the value for x:");
scanf("%d",&x);
printf("Enter the value for n:");
scanf("%d",&n);
if(n <= 0 || x <= 0)
{
printf("Incorrect Value!!\n\n");
}
else
{
printf("The value is valid!!\n\n");
}
for(i = 1;i <= n; i++)
{
geo_sum = geo_sum + pow(x,i);
}
printf("The Sum of Series = %d\n",geo_sum);
system("PAUSE");
return 0;
}
Output
The input values for the program is
1 + 2 + 22 + 23 + 24 + 25 + 26 + 27 + 28 + 29
= 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512 + 1024
= 2047
Therefore, the output is correct.
Enter the value for x:2
Enter the value for n:10
The value is valid!!
The Sum of Series = 2047
Press any key to continue . . . _